Find the limit of $\left(\frac{x+2}{x}\right)^{\left(x+1\right)}$ as $x$ approaches $\infty $

Step-by-step Solution

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Final answer to the problem

$e^{2}$
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Step-by-step Solution

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  • Integrate by partial fractions
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1

Rewrite the limit using the identity: $a^x=e^{x\ln\left(a\right)}$

$\lim_{x\to\infty }\left(e^{\left(x+1\right)\ln\left(\frac{x+2}{x}\right)}\right)$

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$\lim_{x\to\infty }\left(e^{\left(x+1\right)\ln\left(\frac{x+2}{x}\right)}\right)$

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Learn how to solve problems step by step online. Find the limit of ((x+2)/x)^(x+1) as x approaches infinity. Rewrite the limit using the identity: a^x=e^{x\ln\left(a\right)}. Apply the power rule of limits: \displaystyle{\lim_{x\to a}f(x)^{g(x)} = \lim_{x\to a}f(x)^{\displaystyle\lim_{x\to a}g(x)}}. The limit of a constant is just the constant. Rewrite the product inside the limit as a fraction.

Final answer to the problem

$e^{2}$

Exact Numeric Answer

$7.3890561$

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Function Plot

Plotting: $\left(\frac{x+2}{x}\right)^{\left(x+1\right)}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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