Integrate the function $\frac{-3\left(x^2-2x-1\right)}{x^3-x^2+x-1}$ from $2$ to $- \infty $

Step-by-step Solution

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Final answer to the problem

The integral diverges.

Step-by-step Solution

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  • Integrate by partial fractions
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1

Take out the constant $-3$ from the integral

$-3\int\frac{x^2-2x-1}{x^3-x^2+x-1}dx$

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$-3\int\frac{x^2-2x-1}{x^3-x^2+x-1}dx$

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Learn how to solve definite integrals problems step by step online. Integrate the function (-3(x^2-2x+-1))/(x^3-x^2x+-1) from 2 to -infinity. Take out the constant -3 from the integral. We can factor the polynomial x^3-x^2+x-1 using the rational root theorem, which guarantees that for a polynomial of the form a_nx^n+a_{n-1}x^{n-1}+\dots+a_0 there is a rational root of the form \pm\frac{p}{q}, where p belongs to the divisors of the constant term a_0, and q belongs to the divisors of the leading coefficient a_n. List all divisors p of the constant term a_0, which equals -1. Next, list all divisors of the leading coefficient a_n, which equals 1. The possible roots \pm\frac{p}{q} of the polynomial x^3-x^2+x-1 will then be.

Final answer to the problem

The integral diverges.

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Function Plot

Plotting: $\frac{-3\left(x^2-2x-1\right)}{x^3-x^2+x-1}$

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

See formulas (3)

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