Solve the differential equation $y^{\prime}=\sin\left(x-y+1\right)$

Step-by-step Solution

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Final answer to the problem

$y=-2\arctan\left(\frac{x+C_1}{x+C_0}\right)+x+1$
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Step-by-step Solution

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  • Exact Differential Equation
  • Linear Differential Equation
  • Separable Differential Equation
  • Homogeneous Differential Equation
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
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1

Rewrite the differential equation using Leibniz notation

Learn how to solve differential equations problems step by step online.

$\frac{dy}{dx}=\sin\left(x-y+1\right)$

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Learn how to solve differential equations problems step by step online. Solve the differential equation y^'=sin(x-y+1). Rewrite the differential equation using Leibniz notation. When we identify that a differential equation has an expression of the form Ax+By+C, we can apply a linear substitution in order to simplify it to a separable equation. We can identify that x-y+1 has the form Ax+By+C. Let's define a new variable u and set it equal to the expression. Isolate the dependent variable y. Differentiate both sides of the equation with respect to the independent variable x.

Final answer to the problem

$y=-2\arctan\left(\frac{x+C_1}{x+C_0}\right)+x+1$

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Function Plot

Plotting: $y=-2\arctan\left(\frac{x+C_1}{x+C_0}\right)+x+1$

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Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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