Final answer to the problem
$25e\log \left(2\right)e\cdot 5bgi\frac{\frac{nar^2ay}{l}}{qua\cdot dx=2.15}f\cdot 2^{\left(3x-2\right)}=9^x\left(3x-2\right)\left(3\log \left(2\right)x-2\log \left(2\right)\right)nr^2ay\cdot da$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
Multiply $5$ times $5$
Learn how to solve multiply powers of same base problems step by step online.
$25e\log \left(2\right)e\cdot 5bgi\frac{\frac{nar\cdot ray}{l}}{qua\cdot dx=2.15}f\cdot 2^{\left(3x-2\right)}=9^x\left(3x-2\right)\left(3\log \left(2\right)x-2\log \left(2\right)\right)nr\cdot ray\cdot da$
Learn how to solve multiply powers of same base problems step by step online. Simplify the algebraic expression (begi((narray)/l)/(quadx=2.15)f*52^(3x-2.0)=9^x)5(3x-2.0)log(2)*5(3xlog(2)-2.0log(2))*endarray. Multiply 5 times 5. When multiplying two powers that have the same base (r), you can add the exponents. When multiplying two powers that have the same base (r), you can add the exponents.
Final answer to the problem
$25e\log \left(2\right)e\cdot 5bgi\frac{\frac{nar^2ay}{l}}{qua\cdot dx=2.15}f\cdot 2^{\left(3x-2\right)}=9^x\left(3x-2\right)\left(3\log \left(2\right)x-2\log \left(2\right)\right)nr^2ay\cdot da$
