Solve the equation with radicals $3\sqrt[3]{y}+c=x+c$

Step-by-step Solution

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Final answer to the problem

$y=\frac{x^3}{27}$
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Step-by-step Solution

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  • Choose an option
  • Solve for y
  • Solve for c
  • Solve for x
  • Find the derivative
  • Solve by implicit differentiation
  • Solve for y'
  • Find dy/dx
  • Derivative
  • Find the derivative using the definition
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Group the terms of the equation

$3\sqrt[3]{y}=x+c-c$

Learn how to solve equations with cubic roots problems step by step online.

$3\sqrt[3]{y}=x+c-c$

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Unlock the first 3 steps of this solution

Learn how to solve equations with cubic roots problems step by step online. Solve the equation with radicals 3y^(1/3)+c=x+c. Group the terms of the equation. Cancel like terms c and -c. Removing the variable's exponent raising both sides of the equation to the power of 3. The power of a product is equal to the product of it's factors raised to the same power.

Final answer to the problem

$y=\frac{x^3}{27}$

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Function Plot

Plotting: $3\sqrt[3]{y}+c-x-c$

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Got a different answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Equations with Cubic Roots

Those equations that they degree (greatest exponent) equals 3.

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