Final answer to the problem
$f\left(x\right)=\frac{3x^2-19x+20}{\log \left(4x-3x^2\right)}-\frac{1}{3}\log_{2}\left(9x-9\right)$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
Using the power rule of logarithms: $\log_a(x^n)=n\cdot\log_a(x)$
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$f\left(x\right)=\frac{3x^2-19x+20}{\log \left(4x-3x^2\right)}- \left(\frac{1}{3}\right)\log_{2}\left(9x-9\right)$
Learn how to solve problems step by step online. Simplify the expression f(x)=(3x^2-19x+20)/log(4*x+-3*x^2)-log2((9*x+-9)^(1/3)). Using the power rule of logarithms: \log_a(x^n)=n\cdot\log_a(x). Multiply the fraction and term in - \left(\frac{1}{3}\right)\log_{2}\left(9x-9\right).
Final answer to the problem
$f\left(x\right)=\frac{3x^2-19x+20}{\log \left(4x-3x^2\right)}-\frac{1}{3}\log_{2}\left(9x-9\right)$
