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$\left(4x-x^2\right)dx-\frac{dy}{y}=0$
$\sec^2x+\csc^2x=\frac{\csc^2\left(x\right)}{\cos^2\left(x\right)}$
$\int\frac{1}{\sqrt{8-t}}dx$
$\frac{a^8}{b^3}^6$
$3x^3-9x^2+6x^4$
$7mh+23u-2kn+2mh$
$\left(-2+5\cdot y^7\right)\cdot\left(7y^2-y\right)$
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