Final answer to the problem
$\left(x-2\right)\left(x+10\right)$
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Step-by-step Solution
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- Choose an option
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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1
Factor the trinomial $x^2+8x-20$ finding two numbers that multiply to form $-20$ and added form $8$
$\begin{matrix}\left(-2\right)\left(10\right)=-20\\ \left(-2\right)+\left(10\right)=8\end{matrix}$
2
Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values
$\left(x-2\right)\left(x+10\right)$
Final answer to the problem
$\left(x-2\right)\left(x+10\right)$
