Factor the expression $2x^2-x+3$

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Final answer to the problem

$2\left(x-\frac{1}{4}\right)^2+2\cdot \left(\frac{3}{2}-\frac{1}{16}\right)$
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Step-by-step Solution

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  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
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Use the complete the square method to factor the trinomial of the form $ax^2+bx+c$. Take common factor $a$ ($2$) to all terms

$2\left(x^2-\frac{1}{2}x+\frac{3}{2}\right)$

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$2\left(x^2-\frac{1}{2}x+\frac{3}{2}\right)$

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Learn how to solve problems step by step online. Factor the expression 2x^2-x+3. Use the complete the square method to factor the trinomial of the form ax^2+bx+c. Take common factor a (2) to all terms. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Factor the perfect square trinomial x^2+-\frac{1}{2}x+\frac{1}{16}. Multiply the fraction and term in - \frac{1}{4}.

Final answer to the problem

$2\left(x-\frac{1}{4}\right)^2+2\cdot \left(\frac{3}{2}-\frac{1}{16}\right)$

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Function Plot

Plotting: $2\left(x-\frac{1}{4}\right)^2+2\cdot \left(\frac{3}{2}-\frac{1}{16}\right)$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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