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- Integrate by partial fractions
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The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$.
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$\sqrt[6]{\left(x^2-1\right)\left(x^2+1\right)\left(x^4+1\right)+1},\:x=6$
Learn how to solve numerical value of an algebraic expression problems step by step online. Find the numerical value of the expression ((x-1)(x+1)(x^2+1)(x^4+1)+1)^(1/6);x=6. The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Simplify \left(x^2\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals 2. The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2..
