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- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
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Express the numbers in the equation as logarithms of base $2$
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$\log_{2}\left(x+3\right)=\log_{2}\left(2^{5}\right)-\log_{2}\left(x-1\right)$
Learn how to solve problems step by step online. Solve the logarithmic equation log2(x+3)=5-log2(x+-1). Express the numbers in the equation as logarithms of base 2. The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). For two logarithms of the same base to be equal, their arguments must be equal. In other words, if \log(a)=\log(b) then a must equal b. We need to isolate the dependent variable x, we can do that by simultaneously subtracting 3 from both sides of the equation.