Solve the differential equation $\left(y+1\right)dx-x\cdot dy=0$

Step-by-step Solution

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asin
acos
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sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Final answer to the problem

$y=C_1x-1$
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Step-by-step Solution

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  • Exact Differential Equation
  • Linear Differential Equation
  • Separable Differential Equation
  • Homogeneous Differential Equation
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
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Multiplying polynomials $dx$ and $y+1$

Learn how to solve integration by substitution problems step by step online.

$ydx+dx-x\cdot dy=0$

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Learn how to solve integration by substitution problems step by step online. Solve the differential equation (y+1)dx-xdy=0. Multiplying polynomials dx and y+1. Group the terms of the equation. Multiply both sides of the equation by -1. Factor the polynomial ydx+dx by it's greatest common factor (GCF): dx.

Final answer to the problem

$y=C_1x-1$

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Function Plot

Plotting: $\left(y+1\right)dx-x\cdot dy$

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Answer Assistant

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Got a different answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Integration by Substitution

In calculus, integration by substitution, also known as u-substitution, is a method for finding integrals. Using the fundamental theorem of calculus often requires finding an antiderivative.

Used Formulas

See formulas (2)

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