Exercise
$\frac{dy}{dx}\left(\left(x+y\right)^3=x^3+y^3\right)$
Step-by-step Solution
Learn how to solve problems step by step online. Expand the expression dy/dx((x+y)^3=x^3+y^3). Apply the rule of the cube of a binomial for \left(x+y\right)^3. Multiply the single term x^2+2xy+y^2 by each term of the polynomial \left(x+y\right). Multiply the single term x by each term of the polynomial \left(x^2+2xy+y^2\right). When multiplying exponents with same base you can add the exponents: x^2x.
Expand the expression dy/dx((x+y)^3=x^3+y^3)
Final answer to the exercise
$\frac{dy}{dx}x^{3}+3x^2y+3xy^2+y^{3}=x^3+y^3$