$\left(\frac{1}{4}x+\frac{2}{5}x^3\right)^3$

$x^6+2x^3+1$

$\int\left(\frac{x^2+3x+2}{x+1}\right)dx$

$\frac{15x^5y^2}{-5x^3y^3}$

$y'+3y=2$

$\frac{d}{dx}\left(x\right)=\:\frac{x\left(1+x^2\right)^3}{\left(1+x^3\right)^{\frac{1}{3}}}$