$\frac{1}{1-\sin^2x}$
$\lim_{x\to0}\left(\frac{sin^6x}{x}\right)$
$senx\:=\:0.2$
$-\left(-7\right)-\left(-7\right)\left(+3-3\right)$
$\left(-1\right)\cdot\left(-4\right)\cdot\left(-1\right)$
$5x^2+\left(3x-3x^2\right)$
$n\:2-\:3n\:+\:8\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:if\:n\:=\:4\:$
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