$3x-10<5-2x$
$\left(-\frac{8}{\left(-5+3\right)}+\frac{12}{\left(-2+2\cdot4\right)}\right)$
$\lim_{x\to\infty}\left(\frac{1}{x\left(x+2\right)}\right)dx$
$2x^4+6^3-56x^2$
$\left(4b^4+2c^3\right)\left(4b^4-2c^3\right)$
$x^2=6x-9$
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