Find the integral int((2y^4)/(y^3-y^2y+-1))dx

 Exercise

$\int\frac{2y^4}{y^3-y^2+y-1}\:\:\:dx$

 

Take out the constant $2$ from the integral

$2\int\frac{y^4}{y^3-y^2+y-1}dx$

 

The integral of a constant is equal to the constant times the integral's variable

$2\left(\frac{y^4}{y^3-y^2+y-1}\right)x$

 

Multiplying the fraction by $2x$

$\frac{2y^4x}{y^3-y^2+y-1}$

 

As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$

$\frac{2y^4x}{y^3-y^2+y-1}+C_0$

$\frac{2y^4x}{y^3-y^2+y-1}+C_0$

 Try other ways to solve this exercise

Can't find a method? Tell us so we can add it.