$3y^2-y=0$
$\frac{x^4+3x^3-2x^2+1}{x^2-1}$
$\int\left(\frac{x^2}{x+4}\right)dx$
$\left(7x\right)+\left(5yz\right)^2$
$3\cdot4-2\cdot\left(5-11\right)-18$
$3x^3+\frac{1}{4}x^2$
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