$\frac{d}{dx}\frac{x^2+1}{x^3+x-2}$
$6x^2\cdot\sqrt[3]{x}$
$\frac{d^2}{dx^2}\sqrt{3x^2+1}$
$\left(1+x^2\right)y'+1+y^2=0$
$4x^3+\frac{3}{7}x^2-2x+3+6x^2+9$
$\frac{dy}{dx}=2x\left(1-y\right)\:y\left(0\right)=0$
$10-3x-x^2<0$
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