Final answer to the problem
$\frac{\left(\frac{11}{10}\right)^4-1}{\left(\frac{121}{100}+1\right)\cdot \left(\frac{14641}{10000}-\frac{121}{100}+1\right)}$
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Step-by-step Solution
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- Find the integral
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1
Factor the sum or difference of cubes using the formula: $a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2)$
$\frac{\left(\frac{11}{10}\right)^4-1}{\left(\sqrt[3]{\left(\frac{11}{10}\right)^6}+\sqrt[3]{1}\right)\left(\sqrt[3]{\left(\left(\frac{11}{10}\right)^6\right)^{2}}-\sqrt[3]{\left(\frac{11}{10}\right)^6}\sqrt[3]{1}+\sqrt[3]{\left(1\right)^{2}}\right)}$
Learn how to solve division of numbers problems step by step online. Divide ((11/10)^4-1)/((11/10)^6-1). Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2). Calculate the power \left(\frac{11}{10}\right)^6. Calculate the power \sqrt[3]{1}. Calculate the power \left(\frac{11}{10}\right)^6.
Final answer to the problem
$\frac{\left(\frac{11}{10}\right)^4-1}{\left(\frac{121}{100}+1\right)\cdot \left(\frac{14641}{10000}-\frac{121}{100}+1\right)}$
Exact Numeric Answer
$0.167451$
