Prove the trigonometric identity $\frac{\sin\left(x\right)}{1+\cos\left(x\right)}+\frac{1+\cos\left(x\right)}{\sin\left(x\right)}=2\csc\left(x\right)$

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Final answer to the problem

true

Step-by-step Solution

How should I solve this problem?

  • Prove from LHS (left-hand side)
  • Prove from RHS (right-hand side)
  • Express everything into Sine and Cosine
  • Exact Differential Equation
  • Linear Differential Equation
  • Separable Differential Equation
  • Homogeneous Differential Equation
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
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Starting from the left-hand side (LHS) of the identity

$\frac{\sin\left(x\right)}{1+\cos\left(x\right)}+\frac{1+\cos\left(x\right)}{\sin\left(x\right)}$

Learn how to solve product rule of differentiation problems step by step online.

$\frac{\sin\left(x\right)}{1+\cos\left(x\right)}+\frac{1+\cos\left(x\right)}{\sin\left(x\right)}$

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Learn how to solve product rule of differentiation problems step by step online. Prove the trigonometric identity sin(x)/(1+cos(x))+(1+cos(x))/sin(x)=2csc(x). Starting from the left-hand side (LHS) of the identity. The least common multiple (LCM) of a sum of algebraic fractions consists of the product of the common factors with the greatest exponent, and the uncommon factors. Obtained the least common multiple (LCM), we place it as the denominator of each fraction, and in the numerator of each fraction we add the factors that we need to complete. Simplify the numerators.

Final answer to the problem

true

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Function Plot

Plotting: $true$

Main Topic: Product Rule of differentiation

The product rule is a formula used to find the derivatives of products of two or more functions. It may be stated as $(f\cdot g)'=f'\cdot g+f\cdot g'$

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