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Solve the quadratic equation $\frac{1}{7}y^2-\frac{2}{5}=\frac{7}{3}y$

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Solution

Formulas

Videos

Algebra 2 - Learn to describe and solve for the zeros using completing the square 4x^2 - 4x - 1 = 0

https://www.youtube.com/watch?v=0lpMs0iXm2E

Algebra 2 - using the square root method to solve a quadratic equation 4x^2 - 4x + 1 = 9

https://www.youtube.com/watch?v=90FQ2oLoEEQ

Tutorial - Learn how to apply the square root method to solve a quadratic ex 9, y=(1/2)x^2 - (2/9)

https://www.youtube.com/watch?v=qgPR9fykzFM

How to factor a quadratic equation when c=0 - Free Math Help - Online Tutor

https://www.youtube.com/watch?v=YWh2eUXonC0

Solving a quadratic equation with imaginary solutions

https://www.youtube.com/watch?v=welGt70_Ax8

Pre-Calculus - Using the square root method to solve a quadratic equation, (1/2)x^2 + 3 = 19

https://www.youtube.com/watch?v=dvE_W89LrqA

Function Plot

Plotting: $\frac{1}{7}y^2-\frac{2}{5}+\frac{7}{3}y$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Implicit Differentiation

Implicit differentiation makes use of the chain rule to differentiate implicitly defined functions. For differentiating an implicit function y(x), defined by an equation R(x, y) = 0, it is not generally possible to solve it explicitly for y(x) and then differentiate. Instead, one can differentiate R(x, y) with respect to x and y and then solve a linear equation in dy/dx for getting explicitly the derivative in terms of x and y.

Used Formulas

See formulas (3)

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