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Find the higher order ($2$) derivative of $\sin\left(\cos\left(2x\right)\right)$

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Calculus: Derivatives 2 | Taking derivatives | Differential Calculus | Khan Academy

https://www.youtube.com/watch?v=ay8838UZ4nM

Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=TDJ5nXWEkWM

Worked example: Parametric arc length | AP Calculus BC | Khan Academy

https://www.youtube.com/watch?v=F3KyoI26fKI

Calculus - Find the derivative of natural logarithm using product property, d(ln(2x))/dx

https://www.youtube.com/watch?v=urYZhqwUTI0

Pre-Calculus - How to simplify a trig expression using co-function, sin((pi/2) -x)/cos((pi/2) -x)

https://www.youtube.com/watch?v=LxdYYK2mnx4

Function Plot

Plotting: $-4\sin\left(\cos\left(2x\right)\right)\sin\left(2x\right)^2-4\cos\left(\cos\left(2x\right)\right)\cos\left(2x\right)$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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