Find the higher order ($3$) derivative of $\sqrt[3]{6x+1}$

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Function Plot

Plotting: $\frac{80}{\sqrt[3]{\left(6x+1\right)^{8}}}$

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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Higher-order derivatives

The second, third, fourth derivative of a function (and so on) are known as higher order derivatives.

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