Find the derivative of $\arctan\left(\sqrt{x}\right)$

Step-by-step Solution

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asinh
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Final answer to the problem

$\frac{1}{2\left(1+x\right)\sqrt{x}}$
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Step-by-step Solution

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  • Find the derivative using the definition
  • Find the derivative using the product rule
  • Find the derivative using the quotient rule
  • Find the derivative using logarithmic differentiation
  • Find the derivative
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
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1

Taking the derivative of arctangent

$\frac{1}{1+\left(\sqrt{x}\right)^2}\frac{d}{dx}\left(\sqrt{x}\right)$

Learn how to solve differential calculus problems step by step online.

$\frac{1}{1+\left(\sqrt{x}\right)^2}\frac{d}{dx}\left(\sqrt{x}\right)$

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Learn how to solve differential calculus problems step by step online. Find the derivative of arctan(x^(1/2)). Taking the derivative of arctangent. Cancel exponents \frac{1}{2} and 2. The power rule for differentiation states that if n is a real number and f(x) = x^n, then f'(x) = nx^{n-1}. Multiplying fractions \frac{1}{1+x} \times \frac{1}{2}.

Final answer to the problem

$\frac{1}{2\left(1+x\right)\sqrt{x}}$

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Function Plot

Plotting: $\frac{1}{2\left(1+x\right)\sqrt{x}}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

Used Formulas

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