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Find the derivative of $\arccos\left(5x\right)$

Step-by-step Solution

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Solution

Formulas

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Final answer to the problem

$\frac{-5}{\sqrt{1-25x^2}}$
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Learn how to solve inverse trigonometric functions differentiation problems step by step online. Find the derivative of arccos(5x). Taking the derivative of arccosine. The power of a product is equal to the product of it's factors raised to the same power. Multiply -1 times 25. The derivative of the linear function times a constant, is equal to the constant.

Final answer to the problem

$\frac{-5}{\sqrt{1-25x^2}}$

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Function Plot

Plotting: $\frac{-5}{\sqrt{1-25x^2}}$

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5
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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\frac{d}{dx}\arcsin\left(\sqrt{x}\right)$

$\frac{d}{dx}\left(\arcsin\left(\sqrt{2x}\right)\right)$

$\frac{d}{dx}\left(\arccot\left(\sqrt{x}\right)\right)$

$\frac{d}{dx}\left(\arcsin\sqrt{x}\right)$

$\frac{d}{dx}\left(\arctan\left(x-\sqrt{1+x^2}\right)\right)$

$\frac{d}{dx}\arccos\left(\sqrt{x}\right)$

$\frac{d}{dx}\left(x^2\arccos\left(x\right)\right)$

Main Topic: Inverse trigonometric functions differentiation

Describes how to find the derivative of the inverse of the trigonometric functions sine, cosine, tangent, etc.

Used Formulas

See formulas (3)

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