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Find the derivative of $\arctan\left(\pi \arccos\left(4x^2\right)\mathrm{cosh}\left(e^{\left(x^2\right)}\right)\right)$

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Solution

Formulas

Videos

Implicit Differentiation - Find The First &amp; Second Derivatives

https://www.youtube.com/watch?v=-XQDh6Z6DPI

how to take the derivative of arctan with product rule and chain

https://www.youtube.com/watch?v=8iyGt6kn9kI

Calculus - How to use implicit differentiation with the square root for chain and product rule

https://www.youtube.com/watch?v=hQYG9yPrLco

Derivatives of Composite Functions - Chain Rule, Product & Quotient Rule - Calculus Review

https://www.youtube.com/watch?v=vNXjMTv4vHs

Learn how to use the product rule to find the derivative

https://www.youtube.com/watch?v=6CnOz7GefTg

Finding The Tangent Line Equation With Derivatives - Calculus Problems

https://www.youtube.com/watch?v=5-TKfOzwu9w

Function Plot

Plotting: $\frac{\pi }{1+\pi ^2\arccos\left(4x^2\right)^2\mathrm{cosh}\left(e^{\left(x^2\right)}\right)^2}\left(\frac{-8x\mathrm{cosh}\left(e^{\left(x^2\right)}\right)}{\sqrt{1-16x^{4}}}+2e^{\left(x^2\right)}x\arccos\left(4x^2\right)\mathrm{sinh}\left(e^{\left(x^2\right)}\right)\right)$

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Similar Problems Solved

$\frac{d}{dx}\left(\arcsin\left(x^3\right)\right)$

$\frac{d}{dx}\arcsin\left(\sqrt{x}\right)$

$\frac{d}{dx}\left(\arcsin\left(\sqrt{2x}\right)\right)$

$\frac{d}{dx}\left(\arccot\left(\sqrt{x}\right)\right)$

$\frac{d}{dx}\left(\arcsin\sqrt{x}\right)$

$\frac{d}{dx}\left(\arctan\left(x-\sqrt{1+x^2}\right)\right)$

$\frac{d}{dx}\arccos\left(\sqrt{x}\right)$

Main Topic: Product Rule of differentiation

The product rule is a formula used to find the derivatives of products of two or more functions. It may be stated as $(f\cdot g)'=f'\cdot g+f\cdot g'$

Used Formulas

See formulas (5)

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