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Algebra Baldor
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Find the derivative of $\arccos\left(x\right)$

Used Formulas

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asin
acos
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acot
asec
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sinh
cosh
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coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Solution

Formulas

Videos

Derivatives of inverse trigonometric functions

$\frac{d}{dx}\left(\arccos\left(\theta \right)\right)=\frac{-1}{\sqrt{1-\theta ^2}}\frac{d}{dx}\left(\theta \right)$

Basic Derivatives

· Derivative of the linear function
$\frac{d}{dx}\left(x\right)=1$

Function Plot

Plotting: $\frac{-1}{\sqrt{1-x^2}}$

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\frac{d}{dx}\left(\arcsin\left(3x\right)\right)$

$\frac{d}{dx}\left(\arcsin\left(4x\right)\right)$

$\frac{d}{dx}\left(\arctan\left(2x\right)\right)$

$\frac{d}{dx}\left(\arccos\left(2x\right)\right)$

$\frac{d}{dx}\left(\arcsin\left(\frac{x}{6}\right)\right)$

$\frac{d}{dx}\arcsin\left(\sqrt{x}\right)$

$\frac{d}{dx}\left(\arcsin\left(-4x\right)\right)$

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

Used Formulas

See formulas (2)

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