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Find the derivative of $\mathrm{arccot}\left(\sqrt{x}\right)$

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Solution

Formulas

Videos

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

Given the Value of Cotangent Find the Angle Measurement

https://www.youtube.com/watch?v=utG5sTrwkyg

How do we find the period of our trigonometric graphs sine and cosine

https://www.youtube.com/watch?v=yZLeN_9jjGg

Given the Value Cosecant Find the Angle on the Unit Circle

https://www.youtube.com/watch?v=IXehHHxIvRs

How to Find the Angle Given a Trigonometric Equation

https://www.youtube.com/watch?v=jllu5VSsutM

Calculus - Find the derivative of the inverse of a radical equation, f(x)=sqrt(x^2 +6x); find g'(4)

https://www.youtube.com/watch?v=ErarY1CS-bY

Function Plot

Plotting: $\frac{-1}{2\left(1+x\right)\sqrt{x}}$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\frac{d}{dx}\left(\arcsin\left(\sqrt{2x}\right)\right)$

$\frac{d}{dx}\left(\arccot\left(\sqrt{x}\right)\right)$

$\frac{d}{dx}\left(\arcsin\sqrt{x}\right)$

$\frac{d}{dx}\left(\arctan\left(x-\sqrt{1+x^2}\right)\right)$

$\frac{d}{dx}\arccos\left(\sqrt{x}\right)$

$\frac{d}{dx}\left(x^2\arccos\left(x\right)\right)$

$\frac{d}{dx}\arctan\left(x-\sqrt{1+x^2}\right)$

Main Topic: Inverse trigonometric functions differentiation

Describes how to find the derivative of the inverse of the trigonometric functions sine, cosine, tangent, etc.

Used Formulas

See formulas (2)

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