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Find the derivative using logarithmic differentiation method $\frac{d}{dx}\left(\cos\left(x\right)^{\left(\sqrt{x}\right)}\right)$

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 Solution

 Videos

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=TDJ5nXWEkWM

Negative powers differentiation | Derivative rules | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=W233qRK6HPs

Calculus: Derivatives 2 | Taking derivatives | Differential Calculus | Khan Academy

https://www.youtube.com/watch?v=ay8838UZ4nM

Calculus - Find the derivative of natural logarithm using product property, d(ln(2x))/dx

https://www.youtube.com/watch?v=urYZhqwUTI0

Find the value of x when 2 functions are set equal to each other

https://www.youtube.com/watch?v=8x7SOl_oHPM

 Function Plot

Plotting: $\left(\frac{\ln\left(\cos\left(x\right)\right)}{2\sqrt{x}}-\sqrt{x}\tan\left(x\right)\right)\cos\left(x\right)^{\left(\sqrt{x}\right)}$

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9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Rationals and Irrationals

A rational term is an algebraic term that doesn't have literal part inside a radical. An irrational term does have literal part inside a radical.

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