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Find the derivative $\frac{d}{dx}\left(\frac{\left(x^5+3x\right)^4}{\cos\left(x\right)}\right)$

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Solution

Videos

Pre-Calculus - How to simplify a trigonometric expression by squaring a binomial (sin(x)+cos(x))^2

https://www.youtube.com/watch?v=e5IczuZxvVI

Tutorial - Simplify a trigonometric expression and then find the sum ex 31, (sinx/cscx) + (cosx)^2

https://www.youtube.com/watch?v=gim3YN7vOw8

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

Limits by factoring | Limits and continuity | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=EAa3J_nDkoI

Learn how to simplify an expression to find the derivative

https://www.youtube.com/watch?v=AJeW23c_BI8

How to find the derivative of an expression then simplifying

https://www.youtube.com/watch?v=OcYK5gUOSac

Function Plot

Plotting: $\frac{4\left(x^5+3x\right)^{3}\left(5x^{4}+3\right)\cos\left(x\right)+\left(x^5+3x\right)^4\sin\left(x\right)}{\cos\left(x\right)^2}$

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◻/◻
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÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\left(\sin\left(x\right)+\cos\left(x\right)\right)^2$

$1+cot^2x$

$tan\left(x\right)csc\left(x\right)$

$\tan\left(x\right)\csc\left(x\right)$

$\frac{2+\tan^2\left(x\right)}{\sec^2\left(x\right)}-1$

$csc^2x-1$

$\frac{2+tan^2x}{sec^2x}-1$

Main Topic: Simplify Trigonometric Expressions

Simplification of trigonometric expressions consists of rewriting an expression with trigonometric functions in a simpler form. To perform this task, we usually use the most common trigonometric identities, and some algebra.

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