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Find the implicit derivative $\frac{d}{dx}\left(\sqrt{x+y}=x-y\right)$

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Solution

Formulas

Videos

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

Algebra 2 - How to find the real zero of a cubic function, y = -1(x - 3)^3 + 1

https://www.youtube.com/watch?v=4dSA02Fzric

Take the natural log of both sides to implicitly derive the equation

https://www.youtube.com/watch?v=Z2A2007DUpI

Calculus: Derivatives 2 | Taking derivatives | Differential Calculus | Khan Academy

https://www.youtube.com/watch?v=ay8838UZ4nM

Calculus - Take the log of both sides to find the derivative, y = (x(x^2 + 1)^2)/(sqrt(2x^2 - 1))

https://www.youtube.com/watch?v=7aF6Ck6ZRxw

Equation of a tangent line | Taking derivatives | Differential Calculus | Khan Academy

https://www.youtube.com/watch?v=1KwW1v__T_0

Function Plot

Plotting: $y^{\prime}=\frac{2\sqrt{x+y}-1}{1+2\sqrt{x+y}}$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

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$\frac{dy}{dx}=y-y^2$

$\frac{dy}{dx}=y\left(y+2\right)$

$\frac{dy}{dx}=\left(1+e^{-x}\right)\left(y^2-1\right)$

$\frac{dy}{dx}=\frac{x}{2x-y}$

$\frac{dy}{dx}=y\left(1-y\right)$

Main Topic: Differential Equations

A differential equation is a mathematical equation that relates some function with its derivatives.

Used Formulas

See formulas (1)

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