Find the implicit derivative $\frac{d}{dx}\left(\arctan\left(x\right)\right)=\frac{1}{1+x^2}$

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https://www.youtube.com/watch?v=mSVrqKZDRF4

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Function Plot

Plotting: $\frac{1}{1+x^2}=\frac{1}{1+x^2}$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Inverse trigonometric functions differentiation

Describes how to find the derivative of the inverse of the trigonometric functions sine, cosine, tangent, etc.

Used Formulas

See formulas (2)

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