$7x+18\ge x+6$
$\frac{3\left(1.9\right)}{\left(1.9\right)-2}$
$8-3+2\cdot6-4-3\cdot\left[\left[7-2\cdot4\right]\right]-12$
$-131\:+\:-530$
$10x^2-x-3$
$\left(b-\frac{3}{2}\right)^3$
$\int\left(x+2\right)\cdot3^{x^2+4x}$
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