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Find the derivative $\frac{d}{dx}\left(\arccos\left(x\right)+b\sin\left(x\right)\right)$ using the sum rule

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Solution

Formulas

Videos

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

How to find the derivative of a function using the sum and difference rule

https://www.youtube.com/watch?v=jhZA0zshUCU

Learning to find the derivative of a polynomial using sum and difference

https://www.youtube.com/watch?v=MprkDy8ZfMo

Calculus - Using power rule with square root to take derivative on a logarithm, d(ln(sqrt(x+1)))/dx

https://www.youtube.com/watch?v=vbgVpjL8ucU

Calculus - Find the derivative of natural logarithm using product property, d(ln(2x))/dx

https://www.youtube.com/watch?v=urYZhqwUTI0

Finding the derivative square root x over x, using power rule

https://www.youtube.com/watch?v=oR6DDJ-rvbQ

Function Plot

Plotting: $\frac{-1}{\sqrt{1-x^2}}+b\cos\left(x\right)$

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0
a
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d
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g
m
n
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v
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x
y
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.
(◻)
+
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×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\frac{d}{dx}\arctan\left(x-\sqrt{1+x^2}\right)$

$\frac{d}{dx}\arccos\left(\sqrt{1-x^2}\right)$

$\frac{d}{dx}\arcsin\left(\sqrt{x}\right)$

$\frac{d}{dx}\left(\arcsin\left(\sqrt{2x}\right)\right)$

$\frac{d}{dx}\left(\arccot\left(\sqrt{x}\right)\right)$

$\frac{d}{dx}\arcsin\left(2x-3\right)$

$\frac{d}{dx}\left(\arcsin\sqrt{x}\right)$

Main Topic: Inverse trigonometric functions differentiation

Describes how to find the derivative of the inverse of the trigonometric functions sine, cosine, tangent, etc.

Used Formulas

See formulas (5)

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