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Find the derivative of $\ln\left(\tan\left(x\right)\right)$

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asin
acos
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sinh
cosh
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asinh
acosh
atanh
acoth
asech
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Solution

Formulas

Videos

Calculus: Derivatives 2 | Taking derivatives | Differential Calculus | Khan Academy

https://www.youtube.com/watch?v=ay8838UZ4nM

Derivative of log_x (for any positive base a­1) | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=2XB4K6T-yKo

Formal and alternate form of the derivative for ln x | Differential Calculus | Khan Academy

https://www.youtube.com/watch?v=m8yC7kR5Fuk

Secant line with arbitrary difference | Derivatives introduction | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=RaNeCD8t01I

Calculus - Find the derivative of the inverse of a radical equation, f(x)=sqrt(x^2 +6x); find g'(4)

https://www.youtube.com/watch?v=ErarY1CS-bY

Calculus - Take the derivative using product rule with natural logarithms,, ln(y) = (x^2)ln(x)

https://www.youtube.com/watch?v=4TpfQj_Wj84

Function Plot

Plotting: $\sec\left(x\right)\csc\left(x\right)$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\frac{d}{dx}\tan\left(x\right)$

$\frac{d}{dx}\left(\sin^2\left(x\right)\right)$

$\frac{d}{dx}\left(ln\left(cos\left(x\right)\right)\right)$

$\frac{d}{dx}\sin\left(x^2\right)$

$\frac{d}{dx}\left(cot\left(x\right)\right)$

$\frac{d}{dx}\sin\left(8x\right)$

$\frac{d}{dx}\left(\ln\left(x\right)\right)^2$

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

Used Formulas

See formulas (3)

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