Final answer to the problem
$\frac{-1}{3\sqrt[3]{x^{4}}}$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Find the derivative using the definition
- Find the derivative using the product rule
- Find the derivative using the quotient rule
- Find the derivative using logarithmic differentiation
- Find the derivative
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Load more...
Can't find a method? Tell us so we can add it.
1
The power rule for differentiation states that if $n$ is a real number and $f(x) = x^n$, then $f'(x) = nx^{n-1}$
Learn how to solve integral calculus problems step by step online.
$-\frac{1}{3}x^{\left(-\frac{1}{3}-1\right)}$
Learn how to solve integral calculus problems step by step online. Find the derivative d/dx(x^(-1/3)) using the power rule. The power rule for differentiation states that if n is a real number and f(x) = x^n, then f'(x) = nx^{n-1}. Applying the property of exponents, \displaystyle a^{-n}=\frac{1}{a^n}, where n is a number. Multiplying fractions -\frac{1}{3} \times \frac{1}{x^{\left|-\frac{4}{3}\right|}}. Multiplying fractions -\frac{1}{3} \times \frac{1}{\sqrt[3]{x^{4}}}.
Final answer to the problem
$\frac{-1}{3\sqrt[3]{x^{4}}}$
