$\frac{2e^{2x}+3}{8}$
$\left(a^2y^5\right)^3\left(a^2y^5\right)^4$
$\int_1^{\infty}\left(\frac{6}{x^4}\right)dx$
$\left(92\cdot47\right)^4$
$\left(3-x^4\right)^3$
$\frac{8x^2+6x+4}{x+2}$
$\sqrt[3]{3^2\sqrt{9}}$
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