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Find the derivative of $\sqrt{2x^2-4}$

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 Solution

 Videos

Calculus - Take the log of both sides to find the derivative, y = (x(x^2 + 1)^2)/(sqrt(2x^2 - 1))

https://www.youtube.com/watch?v=7aF6Ck6ZRxw

Definite integral of rational function | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=4WJUEXIksH0

Algebra 2 - Finding the vertex of a quadratic function y = 2x^2 + 2x + 1

https://www.youtube.com/watch?v=V2udel2WylU

Algebra 2 - Evaluating functions for numeric values, p(x) = 2x^2 - 4x + 1. Find p(2) and p(-1)

https://www.youtube.com/watch?v=POdNjomXHWA

Power Series Representation With Natural Logarithms - Calculus 2

https://www.youtube.com/watch?v=A6JdlY52NFg

How to take the derivative of logarithm base 4

https://www.youtube.com/watch?v=ou6d3whJ1rY

 Function Plot

Plotting: $\frac{2x}{\sqrt{2x^2-4}}$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Integrals involving Logarithmic Functions

They are those integrals where the function that we are integrating is composed only of combinations of logarithmic functions.

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