Final answer to the problem
$\frac{1}{-\left(e^y+1\right)}=\frac{1}{-e^x-1}+C_0$
Got another answer? Verify it here!
Step-by-step Solution
Learn how to solve integration techniques problems step by step online. Solve the differential equation dy/dx=((e^y+1)^2e^(-y))/((e^x+1)^2e^(-x)). Simplify the fraction \frac{\left(e^y+1\right)^2e^{-y}}{\left(e^x+1\right)^2e^{-x}} by e. Multiply -1 times -1. Apply the property of the product of two powers of the same base in reverse: a^{m+n}=a^m\cdot a^n. Group the terms of the differential equation. Move the terms of the y variable to the left side, and the terms of the x variable to the right side of the equality.
Final answer to the problem
$\frac{1}{-\left(e^y+1\right)}=\frac{1}{-e^x-1}+C_0$
