Solve the differential equation $\frac{dy}{dx}=y\left(2-y\right)$

Step-by-step Solution

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Final answer to the problem

$\frac{1}{2}\ln\left|y\right|-\frac{1}{2}\ln\left|-y+2\right|=x+C_0$
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Step-by-step Solution

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  • Exact Differential Equation
  • Linear Differential Equation
  • Separable Differential Equation
  • Homogeneous Differential Equation
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
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1

Group the terms of the differential equation. Move the terms of the $y$ variable to the left side, and the terms of the $x$ variable to the right side of the equality

Learn how to solve integrals by partial fraction expansion problems step by step online.

$\frac{1}{y\left(2-y\right)}dy=dx$

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Learn how to solve integrals by partial fraction expansion problems step by step online. Solve the differential equation dy/dx=y(2-y). Group the terms of the differential equation. Move the terms of the y variable to the left side, and the terms of the x variable to the right side of the equality. Integrate both sides of the differential equation, the left side with respect to y, and the right side with respect to x. Solve the integral \int\frac{1}{y\left(2-y\right)}dy and replace the result in the differential equation. Solve the integral \int1dx and replace the result in the differential equation.

Final answer to the problem

$\frac{1}{2}\ln\left|y\right|-\frac{1}{2}\ln\left|-y+2\right|=x+C_0$

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Function Plot

Plotting: $\frac{dy}{dx}-y\left(2-y\right)$

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6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Integrals by Partial Fraction Expansion

The partial fraction decomposition or partial fraction expansion of a rational function is the operation that consists in expressing the fraction as a sum of a polynomial (possibly zero) and one or several fractions with a simpler denominator.

Used Formulas

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