Find the derivative using logarithmic differentiation method $\frac{d}{dx}\left(\left(1+x\right)^{\frac{1}{x}}\right)$

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Solving: $\frac{d}{dx}\left(\left(1+x\right)^{\frac{1}{x}}\right)$

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

How to take the derivative using chain rule with natural log and cosine

https://www.youtube.com/watch?v=bbK7KtEeULo

Use the product rule to take the derivative of an exponential equation

https://www.youtube.com/watch?v=otqQ3gpE6fQ

Use the quotient rule to take the derivative of a natural logarithm

https://www.youtube.com/watch?v=DjCrbMPwHAA

Taking the derivative of a exponential equation using the quotient rule

https://www.youtube.com/watch?v=kRmiW9OJy54

Pre-Calculus - Condensing a logarithmic expression to one logarithm 2[3lnx - ln(x+1)-ln(x-1)]

https://www.youtube.com/watch?v=HS0--oEAT4I

Function Plot

Plotting: $\frac{\left(x-\ln\left(1+x\right)-x\ln\left(1+x\right)\right)\left(1+x\right)^{\left(\frac{1}{x}-1\right)}}{x^2}$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Simplification of algebraic expressions

The simplification of algebraic expressions consists in rewriting a long and complex expression in an equivalent, but much simpler expression. This simplification can be accomplished through the combined use of arithmetic and algebra rules.

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