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Algebra Baldor
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Find the derivative of $\left(x+1\right)^2$

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Solving: $\frac{d}{dx}\left(\left(x+1\right)^2\right)$
Solve instead: $\frac{dy}{dx}\left(\left(x+1\right)^2\right)$

Solution

Formulas

Videos

How to find the derivative of a function using the sum and difference rule

https://www.youtube.com/watch?v=jhZA0zshUCU

Implicit differentiation with the chain rule and in

https://www.youtube.com/watch?v=TNy-IxD15f0

Implicit Differentiation - Find The First &amp; Second Derivatives

https://www.youtube.com/watch?v=-XQDh6Z6DPI

Learning to find the derivative of a polynomial using sum and difference

https://www.youtube.com/watch?v=MprkDy8ZfMo

Calculus - Using power rule with square root to take derivative on a logarithm, d(ln(sqrt(x+1)))/dx

https://www.youtube.com/watch?v=vbgVpjL8ucU

Finding the derivative square root x over x, using power rule

https://www.youtube.com/watch?v=oR6DDJ-rvbQ

Function Plot

Plotting: $2x+2$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

Find the derivative

$\frac{d}{dx}\left(x^2+y^2\right)$

$\frac{d}{dx}\left(\arctan\left(x-\sqrt{1+x^2}\right)\right)$

$\frac{d}{dx}\arctan\left(x-\sqrt{1+x^2}\right)$

$\frac{d}{dx}\arccos\left(\sqrt{1-x^2}\right)$

$\frac{d}{dx}\ln\left(x^2+1\right)$

$\frac{d}{dx}\left(x\sqrt{x^2-1}\right)$

$\frac{d}{dx}\left(2x+1\right)^3$

Main Topic: Sum Rule of Differentiation

The sum rule is a method to find the derivative of a function that is the sum of two or more functions.

Used Formulas

See formulas (4)

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