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Find the derivative of $\sqrt{1-y^2}$ using the constant rule

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Solving: $\frac{d}{dx}\left(\sqrt{1-y^2}\right)$
Solve instead: $\frac{dy}{dx}\left(\sqrt{1-y^2}\right)$

Solution

Formulas

Videos

Negative powers differentiation | Derivative rules | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=W233qRK6HPs

Definite integral of rational function | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=4WJUEXIksH0

Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=TDJ5nXWEkWM

Implicit Differentiation - Find The First &amp; Second Derivatives

https://www.youtube.com/watch?v=-XQDh6Z6DPI

Find the derivative using the constant rule

https://www.youtube.com/watch?v=XDIyIlWPY-8

Learn how to find the derivative using the constant multiple rule

https://www.youtube.com/watch?v=eDjIvAyWBzk

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Find the derivative

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Main Topic: Constant Rule for Differentiation

The constant rule for differentiation says that the derivative for any constant $k$ is equal to zero.

Used Formulas

See formulas (1)

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