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Find the derivative of $x\sqrt{x^2+30}$

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Solving: $\frac{d}{dx}\left(x\sqrt{x^2+30}\right)$
Solve instead: $\frac{dy}{dx}x\sqrt{x^2+30}$

Solution

Videos

Calculus: Derivatives 2 | Taking derivatives | Differential Calculus | Khan Academy

https://www.youtube.com/watch?v=ay8838UZ4nM

Calculus - Take the log of both sides to find the derivative, y = (x(x^2 + 1)^2)/(sqrt(2x^2 - 1))

https://www.youtube.com/watch?v=7aF6Ck6ZRxw

Algebra 2 - How to find all the roots of a polynomial by factoring, y = 6x^3 + x^2 - x

https://www.youtube.com/watch?v=Qi20wNdicXQ

Algebra 2 - How to find the real zero of a cubic function, y = -1(x - 3)^3 + 1

https://www.youtube.com/watch?v=4dSA02Fzric

Calculus - Find the derivative of the inverse of a radical equation, f(x)=sqrt(x^2 +6x); find g'(4)

https://www.youtube.com/watch?v=ErarY1CS-bY

Algebra 1 - Solve an equation with a rational term 1/x= 3+ 7/x^2+7x ex 2

https://www.youtube.com/watch?v=OjNDpBeMpxI

Function Plot

Plotting: $\sqrt{x^2+30}+\frac{x^2}{\sqrt{x^2+30}}$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\frac{dy}{dx}=y^2-9$

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$\left(y^2+2xy\right)dx-x^2dy=0$

$\frac{dy}{dx}=y-y^2$

$\frac{dy}{dx}=y\left(y+2\right)$

$\frac{dy}{dx}=\left(1+e^{-x}\right)\left(y^2-1\right)$

$\frac{dy}{dx}=\frac{x}{2x-y}$

Main Topic: Differential Equations

A differential equation is a mathematical equation that relates some function with its derivatives.

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