Final answer to the problem
$\frac{dy}{dz}y^{zy}+\ln\left(y\right)-\ln\left(xz\right)=\sqrt{3^{xy}+y}+y^x$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
- Load more...
Can't find a method? Tell us so we can add it.
1
The logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator
$\frac{dy}{dz}y^{zy}+\ln\left(y\right)-\ln\left(xz\right)=\sqrt{3^{xy}+y}+y^x$
Final answer to the problem
$\frac{dy}{dz}y^{zy}+\ln\left(y\right)-\ln\left(xz\right)=\sqrt{3^{xy}+y}+y^x$
