$x-10=4$
$\left(3a+b\right)\left(3a-b\right)$
$-7+\left(-1\right).\left(-1\right)$
$\frac{7}{8}m+\frac{9}{10}-2m-\frac{2}{5}$
$sinacosa=sin\left(2a\right)$
$1+cos2x+2sin^2x=2$
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