Final answer to the problem
$\frac{4}{3}e^{3r}r-\frac{4}{9}e^{3r}+C_0$
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Step-by-step Solution
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- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Integrate using trigonometric identities
- Integrate using basic integrals
- Product of Binomials with Common Term
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1
The integral of a function times a constant ($4$) is equal to the constant times the integral of the function
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$4\int re^{3r}dr$
Learn how to solve problems step by step online. Find the integral int(4re^(3r))dr. The integral of a function times a constant (4) is equal to the constant times the integral of the function. We can solve the integral \int re^{3r}dr by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify or choose u and calculate it's derivative, du. Now, identify dv and calculate v.
Final answer to the problem
$\frac{4}{3}e^{3r}r-\frac{4}{9}e^{3r}+C_0$
