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- Integrate by partial fractions
- Integrate by substitution
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- Integrate using tabular integration
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- Weierstrass Substitution
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- Integrate using basic integrals
- Product of Binomials with Common Term
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Rewrite the expression $\frac{1}{x^2-9}$ inside the integral in factored form
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$\int\frac{1}{\left(x+3\right)\left(x-3\right)}dx$
Learn how to solve problems step by step online. Find the integral int(1/(x^2-9))dx. Rewrite the expression \frac{1}{x^2-9} inside the integral in factored form. Rewrite the fraction \frac{1}{\left(x+3\right)\left(x-3\right)} in 2 simpler fractions using partial fraction decomposition. Expand the integral \int\left(\frac{-1}{6\left(x+3\right)}+\frac{1}{6\left(x-3\right)}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{-1}{6\left(x+3\right)}dx results in: -\frac{1}{6}\ln\left(x+3\right).
