Final answer to the problem
$e^2\cdot \frac{1}{2}t^2+7e^2t+3t+C_0$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Integrate using trigonometric identities
- Integrate using basic integrals
- Product of Binomials with Common Term
- Load more...
Can't find a method? Tell us so we can add it.
1
Rewrite the expression $e^2\left(t+7\right)+3$ inside the integral in factored form
$\int\left(e^2t+7e^2+3\right)dt$
Learn how to solve integrals of polynomial functions problems step by step online. Integrate int((t+7)e^2+3)dt. Rewrite the expression e^2\left(t+7\right)+3 inside the integral in factored form. Expand the integral \int\left(e^2t+7e^2+3\right)dt into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int e^2tdt results in: e^2\cdot \frac{1}{2}t^2. The integral \int7e^2dt results in: 7e^2t.
Final answer to the problem
$e^2\cdot \frac{1}{2}t^2+7e^2t+3t+C_0$
